web: draw isolated points as a connected series and mark unrecorded time in the adaptive audit [CI]

web/display/src/AdaptiveAudit.tsx

@@ -17,12 +17,12 @@ const STATES = [
   { key: 'quiet', label: '平稳', level: 'ok' },
   { key: 'watch', label: '观察', level: 'warn' },
   { key: 'active', label: '活跃', level: 'bad' },
-  { key: 'dead', label: '不通', level: 'none' },
+  { key: 'dead', label: '不通', level: 'dead' },
 ] as const
 type StateKey = (typeof STATES)[number]['key']
 
 const KIND_NAMES: Record<string, string> = { quic_ping: 'QUIC 往返', tcp_ping: 'TCP 往返', tcp_connect: 'TCP 建连', http_request: 'HTTP 请求' }
-const STATE_LABEL: Record<string, string> = { quiet: '平稳', watch: '观察', active: '活跃', dead: '不通' }
+const STATE_LABEL: Record<string, string> = { start: '启动', quiet: '平稳', watch: '观察', active: '活跃', dead: '不通' }
 
 const secondsOf = (b: AdaptiveBucketDto, state: StateKey) => b[`${state}_seconds` as const]
 
@@ -141,6 +141,9 @@ export function AdaptiveAudit({ lineId }: { lineId: string }) {
             <i className={`bar ${s.level}`} /> {s.label}
           </span>
         ))}
+        <span>
+          <i className="bar none" /> 无记录
+        </span>
       </div>
       {data.kinds.map((k) => (
         <Row key={k.kind} kind={k.kind} buckets={k.buckets} step={info.step} />

web/display/src/display.css

@@ -2752,3 +2752,9 @@ input {
   color: var(--app-ink-muted);
   font-size: 13px;
 }
+
+/* 自适应审计里「不通」：比「没有记录」（灰、半透明）深 */
+.bar.dead {
+  background: var(--app-ink-muted);
+  opacity: 1;
+}

web/shared/charts/TimeChart.tsx

@@ -40,10 +40,19 @@ export function fmtOffset(ms: number): string {
   return h > 0 ? `${h}:${two(m)}${sec ? ':' + two(sec) : ''}` : `${m}:${two(sec)}`
 }
 
-/** 有值的格子不到三分之一（而且至少有一个）算稀疏。 */
+/**
+ * 稀疏：有值的点里，前后都是空的（孤立的）占三成以上。每 10 秒才一次的建连放在 5 秒的格子里就是隔一格有一格没有，
+ * 每个点都是孤立的，连不成线，图上什么都看不见；这种序列画出点，并把点连起来。
+ */
 function isSparse(values: (number | null)[]): boolean {
-  const filled = values.filter((v) => v !== null).length
-  return filled > 0 && filled < values.length / 3
+  let filled = 0
+  let isolated = 0
+  for (let i = 0; i < values.length; i++) {
+    if (values[i] === null) continue
+    filled++
+    if ((i === 0 || values[i - 1] === null) && (i === values.length - 1 || values[i + 1] === null)) isolated++
+  }
+  return filled > 0 && isolated / filled >= 0.3
 }
 
 /**